Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Section 9.3 - Area, Volume, and Surface Area - Exercise Set - Page 634: 23


$T=24$ square cm.

Work Step by Step

The area of this figure can be calculated as the sum of the area of the square and the area of the parallelogram. $T=T_1+T_2$ Square: $T_1=a^2$ $T_1=3^2=9$ square cm. Parallelogram: $T_2=h\times a=5\times 3=5\times 3=15$ square cm $T=T_1+T_2=9+15=24$ square cm.
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