## Prealgebra (7th Edition)

$T=24$ square cm.
The area of this figure can be calculated as the sum of the area of the square and the area of the parallelogram. $T=T_1+T_2$ Square: $T_1=a^2$ $T_1=3^2=9$ square cm. Parallelogram: $T_2=h\times a=5\times 3=5\times 3=15$ square cm $T=T_1+T_2=9+15=24$ square cm.