Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.2 - Proportions - Exercise Set - Page 427: 56



Work Step by Step

$\frac{24}{n}=\frac{\frac{8}{15}}{\frac{5}{9}}$ $\Rightarrow$ cross multiply to solve for n $24(\frac{5}{9})=\frac{8}{15}n$ $\Rightarrow$ multiplication property of equality $24(\frac{5}{9})(\frac{15}{8})=\frac{/\!\!8}{/\!\!\!15}n\times\frac{/\!\!\!15}{/\!\!8}$ $\Rightarrow$ simplify $(/\!\!3\times/\!\!8)(\frac{5}{/\!\!3\times/\!\!3})(\frac{/\!\!3\times5}{/\!\!8})=n$ $\Rightarrow$ simplify $25=n$
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