## Prealgebra (7th Edition)

Published by Pearson

# Chapter 6 - Section 6.2 - Proportions - Exercise Set - Page 427: 53

#### Answer

$n=\frac{9}{20}$

#### Work Step by Step

$\frac{\frac{1}{3}}{\frac{3}{8}}=\frac{\frac{2}{5}}{n}$ $\longrightarrow$ cross multiply to solve for n $\frac{1}{3}n=\frac{3}{8}\times\frac{2}{5}$$\longrightarrowmultiply \frac{1}{3}n=\frac{6}{40}$$\longrightarrow$multiplication property of equality $\frac{1}{3}n\times3=\frac{6}{40}\times3$$\longrightarrow divide n=\frac{18}{40}$$\longrightarrow$simplify $n=\frac{18\div2}{40\div2}$ $n=\frac{9}{20}$

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