Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.2 - Proportions - Exercise Set - Page 427: 54

Answer

$n=\frac{2}{21}$

Work Step by Step

$\frac{\frac{7}{9}}{\frac{8}{27}}=\frac{\frac{1}{4}}{n}$ $\longrightarrow$ cross multiply to solve for n $\frac{7}{9}n=\frac{8}{27}\times\frac{1}{4}$$\longrightarrow$multiply $\frac{7}{9}n=\frac{8}{108}$$\longrightarrow$multiplication property of equality $\frac{7}{9}n\times\frac{9}{7}=\frac{8}{108}\times\frac{9}{7}$$\longrightarrow$ multiply $n=\frac{72}{756}$$\longrightarrow$simplify $n=\frac{72\div36}{756\div36}$ $n=\frac{2}{21}$
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