Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.2 - Proportions - Exercise Set - Page 427: 55



Work Step by Step

$\frac{12}{n}=\frac{\frac{2}{3}}{\frac{6}{9}}$ $\Rightarrow$ cross multiply to solve for n $12(\frac{6}{9})=\frac{2}{3}n$ $\Rightarrow$ multiplication property of equality $12(\frac{/\!\!3\times/\!\!2}{/\!\!3\times/\!\!3})\times\frac{/\!\!3}{/\!\!2}=\frac{/\!\!2}{/\!\!3}n\times\frac{/\!\!3}{/\!\!2}$ $\Rightarrow$ simplify $12=n$
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