## Prealgebra (7th Edition)

$\frac{12}{n}=\frac{\frac{2}{3}}{\frac{6}{9}}$ $\Rightarrow$ cross multiply to solve for n $12(\frac{6}{9})=\frac{2}{3}n$ $\Rightarrow$ multiplication property of equality $12(\frac{/\!\!3\times/\!\!2}{/\!\!3\times/\!\!3})\times\frac{/\!\!3}{/\!\!2}=\frac{/\!\!2}{/\!\!3}n\times\frac{/\!\!3}{/\!\!2}$ $\Rightarrow$ simplify $12=n$