Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.2 - Proportions - Exercise Set: 35


$\frac{\frac{2}{3}}{\frac{1}{5}}=\frac{\frac{2}{5}}{\frac{1}{9}}$ false

Work Step by Step

numerator "is to" denominator... $\frac{\frac{2}{3}}{\frac{1}{5}}=\frac{\frac{2}{5}}{\frac{1}{9}}$ Cross multiply to determine if the proportion is true. $\frac{2}{3}\times \frac{1}{9}\overset?=\frac{1}{5}\times \frac{2}{5}$ $\frac{1}{27}\overset?=\frac{2}{25}\ X$
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