Answer
$-6\frac{1}{2}$
Work Step by Step
$\frac{2+\frac{1}{6}}{1-\frac{4}{3}}$
$=(2+\frac{1}{6})\div(1-\frac{4}{3})$
$=(\frac{12}{6}+\frac{1}{6})\div(\frac{3}{3}-\frac{4}{3})$
$=\frac{13}{6}\div(-\frac{1}{3})$
$=-(\frac{13}{6}\div\frac{1}{3})$
$=-(\frac{13}{6}\times\frac{3}{1})$
$=-(\frac{13}{2}\times\frac{1}{1})$
$=-\frac{13}{2}$
$=-6\frac{1}{2}$