Answer
$-\frac{2x}{19}+\frac{8}{19}$
Work Step by Step
$\frac{1-\frac{x}{4}}{2+\frac{3}{8}}$
$=(1-\frac{x}{4})\div(2+\frac{3}{8})$
$=(1-\frac{x}{4})\div(\frac{16}{8}+\frac{3}{8})$
$=(1-\frac{x}{4})\div\frac{19}{8}$
$=(1-\frac{x}{4})\times\frac{8}{19}$
$=\frac{8}{19}(\frac{1}{1}-\frac{x}{4})$
Use the distributive property to distribute $\frac{8}{19}$ to $(\frac{1}{1}-\frac{x}{4})$
$=\frac{8}{19}-\frac{8x}{76}$
$=\frac{8}{19}-\frac{2x}{19}$
$=-\frac{2x}{19}+\frac{8}{19}$ (generally the $x$ term is written before the term with no variable when expressing simplified polynomials)
