Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 285: 50

Answer

$\frac{1}{81}$

Work Step by Step

$(\frac{5}{9}-\frac{2}{3})^{2}$ $=(\frac{5}{9}-\frac{6}{9})^{2}$ $=(-\frac{1}{9})^{2}$ $=[(-\frac{1}{9})\times(-\frac{1}{9})]$ $=(\frac{1}{9}\times\frac{1}{9})$ $=\frac{1}{81}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.