Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 50

Answer

$\frac{1}{81}$

Work Step by Step

$(\frac{5}{9}-\frac{2}{3})^{2}$ $=(\frac{5}{9}-\frac{6}{9})^{2}$ $=(-\frac{1}{9})^{2}$ $=[(-\frac{1}{9})\times(-\frac{1}{9})]$ $=(\frac{1}{9}\times\frac{1}{9})$ $=\frac{1}{81}$
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