Answer
a) $\frac{9}{64}$
b) $\frac{9}{64}$
Work Step by Step
$(\frac{1}{2})^{2} \times (\frac{3}{4})^{2} = \frac{1}{4} \times \frac{9}{16} = \frac{9}{64}$
$(\frac{1}{2}\times\frac{3}{4})^{2} = (\frac{3}{8})^2 = \frac{9}{64}$
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set - Page 285: 62
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