Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.6 - Complex Fractions and Review of Order of Operations - Exercise Set: 45

Answer

$\frac{9}{25}$

Work Step by Step

$(1-\frac{2}{5})^{2}$ $=(\frac{5}{5}-\frac{2}{5})^{2}$ $=(\frac{3}{5})^{2}$ $=\frac{3}{5}\times\frac{3}{5}$ $=\frac{9}{25}$
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