Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.5 - Adding and Subtracting Unlike Fractions - Exercise Set - Page 273: 76

Answer

$\frac{17}{12}$ or $ 1\frac{5}{12}$

Work Step by Step

$ x=\frac{1}{3}$ $y= \frac{3}{4}$ $2x+y= 2 (\frac{1}{3}) + \frac{3}{4}$ $ \frac{2\times1}{3} + \frac{3}{4}= \frac{2}{3}+ \frac{3}{4}$ The least common multiple is 12. Adjust the denominators of the fractions based on the least common multiple. For the first fraction, multiply the numerator and denominator by 4. $ \frac{2}{3} \times \frac{4}{4}= \frac{8}{12}$ For the second fraction, multiply the numerator and denominator by 3. $\frac{3}{4}\times \frac{3}{3}= \frac{9}{12}$ $\frac{8}{12}+ \frac{9}{12}= \frac{17}{12}= 1\frac{5}{12}$
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