Answer
$\frac{22}{12}$ or $1 \frac{5}{6}$
Work Step by Step
$ x=\frac{1}{3}$ $y= \frac{3}{4}$
$2y+x= 2 (\frac{3}{4}) + \frac{1}{3}$
$2 (\frac{3}{4}) + \frac{1}{3}= \frac{2\times 3}{4}+ \frac{1}{3}$
$ \frac{2\times 3}{4}+ \frac{1}{3}= \frac{6}{4}+ \frac{1}{3}$
The least common multiple is 12. Adjust the denominators of the fractions based on the least common multiple. For the first fraction, multiply the numerator and denominator by 3.
$ \frac{6}{4}\times \frac{3}{3}= \frac{18}{12}$
For the second fraction, multiply the numerator and denominator by 4.
$ \frac{1}{3} \times \frac{4}{4}= \frac{4}{12}$
$\frac{18}{12}+ \frac{4}{12}= \frac{22}{12}= 1 \frac{5}{6}$