Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.5 - Adding and Subtracting Unlike Fractions - Exercise Set - Page 273: 75

Answer

$\frac{22}{12}$ or $1 \frac{5}{6}$

Work Step by Step

$ x=\frac{1}{3}$ $y= \frac{3}{4}$ $2y+x= 2 (\frac{3}{4}) + \frac{1}{3}$ $2 (\frac{3}{4}) + \frac{1}{3}= \frac{2\times 3}{4}+ \frac{1}{3}$ $ \frac{2\times 3}{4}+ \frac{1}{3}= \frac{6}{4}+ \frac{1}{3}$ The least common multiple is 12. Adjust the denominators of the fractions based on the least common multiple. For the first fraction, multiply the numerator and denominator by 3. $ \frac{6}{4}\times \frac{3}{3}= \frac{18}{12}$ For the second fraction, multiply the numerator and denominator by 4. $ \frac{1}{3} \times \frac{4}{4}= \frac{4}{12}$ $\frac{18}{12}+ \frac{4}{12}= \frac{22}{12}= 1 \frac{5}{6}$
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