Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.5 - Adding and Subtracting Unlike Fractions - Exercise Set - Page 273: 59

Answer

$\frac{40+9x}{72}$

Work Step by Step

$\frac{5}{9x}+\frac{1}{8} $ The LCD is 72x $\frac{5}{9x}\times\frac{8}{8}+\frac{1}{8}\times\frac{9x}{9x}$ $\frac{40}{72}+\frac{9x}{72}$ $\frac{40+9x}{72}$
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