Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.5 - Adding and Subtracting Unlike Fractions - Exercise Set: 20

Answer

$\frac{10z-1}{12}$

Work Step by Step

LCD is 12. $\frac{5z}{6}-\frac{1}{12}=\frac{5z\times2}{6\times2}-\frac{1}{12}=\frac{10z}{12}-\frac{1}{12}=\frac{10z-1}{12}$
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