Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.5 - Adding and Subtracting Unlike Fractions - Exercise Set: 28

Answer

$\frac{10b-3}{25}$

Work Step by Step

LCD is 25. $\frac{2b}{5}-\frac{3}{25}=\frac{2b\times5}{5\times5}-\frac{3}{25}=\frac{10b}{25}-\frac{3}{25}=\frac{10b-3}{25}$
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