Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 73

Answer

$2\frac{1}{9}$

Work Step by Step

Sum the lengths of the sides. $\frac{2}{9}+\frac{5}{6}+\frac{2}{9}+\frac{5}{6}=\frac{2\times2}{9\times2}+\frac{5\times3}{6\times3}+\frac{2\times2}{9\times2}+\frac{5\times3}{6\times3}=\frac{4}{18}+\frac{15}{18}+\frac{4}{18}+\frac{15}{18}=\frac{4+15+4+15}{18}=\frac{38}{18}$ Reduce. $\frac{38}{18}=38\div18=2R2=2\frac{2}{18}=2\frac{2\div2}{18\div2}=2\frac{1}{9}$
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