Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 81

Answer

$3\frac{3}{4}$

Work Step by Step

$\frac{x}{y+z}=\frac{\frac{1}{2}}{-\frac{2}{3}+\frac{4}{5}}=\frac{\frac{1}{2}}{-\frac{2\times5}{3\times5}+\frac{4\times3}{5\times3}}=\frac{\frac{1}{2}}{-\frac{10}{15}+\frac{12}{15}}=\frac{\frac{1}{2}}{\frac{2}{15}}=\frac{1}{2}\div\frac{2}{15}=\frac{1}{2}\times\frac{15}{2}=\frac{15}{4}=3\frac{3}{4}$
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