Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 321: 75

Answer

$\frac{21}{50}$

Work Step by Step

$\frac{9}{25}+\frac{3}{50}=\frac{9\times2}{25\times2}+\frac{3}{50}=\frac{18}{50}+\frac{3}{50}=\frac{18+3}{50}=\frac{21}{50}$
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