Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 321: 87



Work Step by Step

$7\frac{3}{8}+9\frac{5}{6}+3\frac{1}{12}$ $=7\frac{9}{24}+9\frac{20}{24}+3\frac{1}{12}$ $=16\frac{29}{24}+3\frac{1}{12}$ $=17\frac{5}{24}+3\frac{1}{12}$ $=17\frac{5}{24}+3\frac{2}{24}$ $=20\frac{7}{24}$
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