Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review: 72

Answer

$\frac{5}{18}$

Work Step by Step

$\frac{2\times6}{3\times6}-\frac{2\times2}{9\times2}-\frac{1\times3}{6\times3}=\frac{12}{18}-\frac{4}{18}-\frac{3}{18}=\frac{12-4-3}{18}=\frac{5}{18}$
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