Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Review - Page 320: 69

Answer

$\frac{4y+45}{9y}$

Work Step by Step

$\frac{4}{9}+\frac{5}{y}=\frac{4\times y}{9\times y}+\frac{5\times9}{y\times9}=\frac{4y}{9y}+\frac{45}{9y}=\frac{4y+45}{9y}$
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