Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.2 - Integrated Review - Operations on Polynomials: 6

Answer

$-4a^{3}-12a^{2}$

Work Step by Step

$(2a^{3}-6a^{2}+11)-(6a^{3}+6a^{2}+11)$ $=2a^{3}-6a^{2}+11-6a^{3}-6a^{2}-11$ $=2a^{3}-6a^{3}-6a^{2}-6a^{2}+11-11$ $=-4a^{3}-12a^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.