Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.2 - Integrated Review - Operations on Polynomials - Page 712: 6

Answer

$-4a^{3}-12a^{2}$

Work Step by Step

$(2a^{3}-6a^{2}+11)-(6a^{3}+6a^{2}+11)$ $=2a^{3}-6a^{2}+11-6a^{3}-6a^{2}-11$ $=2a^{3}-6a^{3}-6a^{2}-6a^{2}+11-11$ $=-4a^{3}-12a^{2}$
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