Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.2 - Integrated Review - Operations on Polynomials - Page 712: 16

Answer

$a^{11}$

Work Step by Step

Using the product property for exponents (which states that $a^{m}\times a^{n}=a^{m+n}$, we can conclude that $a\times a^{10}=a^{11}$ Remember that $a$ is equivalent to $a^{1}$
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