Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.2 - Integrated Review - Operations on Polynomials: 24

Answer

$12a^{3}b^{4}$

Work Step by Step

$(-4a^{2}b^{3})(-3ab)$ $=[(-4)\times(-3)](a^{2}\times a)(b^{3}\times b)$ $=(12)(a^{3})(b^{4})$ $=12a^{3}b^{4}$
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