Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.2 - Integrated Review - Operations on Polynomials: 29

Answer

$144a^{38}b^{12}$

Work Step by Step

$(2a^{5}b)^{4}(3a^{9}b^{4})^{2}$ $=(2^{4})[(a^{5})^4](b^{4})(3^{2})[(a^{9})^{2}][(b^{4})^{2}]$ $=(2\times2\times2\times2)(3\times3)(a^{5\times4})(a^{9\times2})(b^{4})(b^{4\times2})$ $=(4\times2\times2)(9)(a^{20})(a^{18})(b^{4})(b^{8})$ $=(8\times2\times9)(a^{20+18})(b^{4+8})$ $=(16\times9)(a^{38})(b^{12})$ $=144a^{38}b^{12}$
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