Answer
$125x^{22}b^{28}$
Work Step by Step
$(5x^{4}y^{6})^{3}(x^{2}y^{2})^{5}$
$=(5^{3})[(x^{4})^3][(y^{6})^3][(x^{2})^5)][(y^{2})^{5}]$
$=(5\times5\times5)(x^{4\times3})(x^{2\times5})(y^{6\times3})(y^{2\times5})$
$=(25\times5)(x^{12})(x^{10})(y^{18})(y^{10})$
$=125(x^{12+10})(y^{18+10})$
$=125x^{22}b^{28}$
