Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Exercise Set 6.5 - Page 399: 21



Work Step by Step

$2x^{2}$ + 7x +3 step 1. Find two first terms whose product is $2x^{2}$ $2x^{2}$ +7x +3 =(2x__)(x__) Step 2. To find the second term of each factor, we must find two integers whose product is 3 and whose sum is 7 List pairs of factors of the constant, 3 (1,3) step 3. The correct factorization of $2x^{2}$ +7x +3 is the one in which the sum of the Outside and Inside products is equal to 7x list of the possible factorization : (x+3)(2x+1)= $2x^{2}$ +7x +3 So, (x+3)(2x+1) is the solution.
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