#### Answer

(x+3)(x-5)

#### Work Step by Step

$x^{2}$ - 2x - 15
step 1. Enter x as the first term of each factor
$x^{2}$ - 2x - 15 = (x__)(x _)
Step 2. To find the second term of each factor, we must find two integers whose product is -15 and whose sum is -2
List pairs of factors of the constant, -15
(1,-15)(-1,15)(3,-5)(-3,5)
step 3. The correct factorization of $x^{2}$ - 2x - 15 is the one in which the sum of the Outside and Inside products is equal to -2x.
So (3,-5) satisfy the condition
$x^{2}$ -2x - 15 = $x^{2}$ +3x -5x - 15 = (x+3)(x-5)