#### Answer

(x+1)(x-5)

#### Work Step by Step

$x^{2}$ - 4x - 5
step 1. Enter x as the first term of each factor
$x^{2}$ - 4x - 5 = (x__)(x _)
Step 2. To find the second term of each factor, we must find two integers whose product is -5 and whose sum is -4
List pairs of factors of the constant, -5
(1,-5)(-1,5)
step 3. The correct factorization of $x^{2}$ - 4x - 5 is the one in which the sum of the Outside and Inside products is equal to -4x.
So (1,-5) satisfy the condition
$x^{2}$ -4x - 5 = $x^{2}$ +x -5x - 5 = (x+1)(x-5)