Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Exercise Set 6.5: 12

Answer

(x+1)(x-5)

Work Step by Step

$x^{2}$ - 4x - 5 step 1. Enter x as the first term of each factor $x^{2}$ - 4x - 5 = (x__)(x _) Step 2. To find the second term of each factor, we must find two integers whose product is -5 and whose sum is -4 List pairs of factors of the constant, -5 (1,-5)(-1,5) step 3. The correct factorization of $x^{2}$ - 4x - 5 is the one in which the sum of the Outside and Inside products is equal to -4x. So (1,-5) satisfy the condition $x^{2}$ -4x - 5 = $x^{2}$ +x -5x - 5 = (x+1)(x-5)
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