Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Exercise Set 6.5 - Page 399: 19



Work Step by Step

$x^{2}$ + 17x+16 step 1. Enter x as the first term of each factor $x^{2}$ + 17x + 16= (x__)(x _) Step 2. To find the second term of each factor, we must find two integers whose product is 16 and whose sum is 17 List pairs of factors of the constant, 16 (1,16)(2,8)(4,4) step 3. The correct factorization of $x^{2}$ +17x +16 is the one in which the sum of the Outside and Inside products is equal to 17x So (1,16) satisfy the condition $x^{2}$ + 17x + 16 = $x^{2}$ +1x+16x + 16 = (x+1)(x+16)
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