## Thinking Mathematically (6th Edition)

$x^{2}$ + 17x+16 step 1. Enter x as the first term of each factor $x^{2}$ + 17x + 16= (x__)(x _) Step 2. To find the second term of each factor, we must find two integers whose product is 16 and whose sum is 17 List pairs of factors of the constant, 16 (1,16)(2,8)(4,4) step 3. The correct factorization of $x^{2}$ +17x +16 is the one in which the sum of the Outside and Inside products is equal to 17x So (1,16) satisfy the condition $x^{2}$ + 17x + 16 = $x^{2}$ +1x+16x + 16 = (x+1)(x+16)