## Thinking Mathematically (6th Edition)

Published by Pearson

# Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Exercise Set 6.5 - Page 399: 20

(x+4)(x- 11)

#### Work Step by Step

$x^{2}$ - 7x - 44 step 1. Enter x as the first term of each factor $x^{2}$ - 7x - 44= (x__)(x _) Step 2. To find the second term of each factor, we must find two integers whose product is -44 and whose sum is -7 List pairs of factors of the constant, -44 (1,-44)(-1,44)(4,-11)(-4,11) step 3. The correct factorization of $x^{2}$ - 7x -44 is the one in which the sum of the Outside and Inside products is equal to -7x So (4,-11) satisfy the condition $x^{2}$ - 7x -44 = $x^{2}$ +4x -11x -44 = (x+4)(x- 11)

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