Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter 5 Test: 9

Answer

$\dfrac{1}{5}$

Work Step by Step

Convert the mixed number to an improper fraction: $=\dfrac{-3}{7} \div \dfrac{-(7 \cdot 2 + 1)}{7} \\=\dfrac{-3}{7} \div \dfrac{-15}{7}$ Use the rule $\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}$: $=\dfrac{-3}{7} \times \dfrac{7}{-15}$ Cancel common factors and then multiply: $\require{cancel} =\dfrac{\cancel{-3}1}{\cancel{7}} \times \dfrac{\cancel{7}}{\cancel{-15}5} \\=\dfrac{1}{5}$
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