Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter 5 Test - Page 337: 21



Work Step by Step

Use the rule $a^{-m} = \dfrac{1}{a^m}, a\ne0$ to obtain: $=\dfrac{1}{8^2} \\=\dfrac{1}{8(8)} \\=\dfrac{1}{64}$
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