## Thinking Mathematically (6th Edition)

$3\sqrt2$
Rationalize the denominator by multiplying $\sqrt2$ to both the numerator and the denominator: $=\dfrac{6 \cdot \sqrt2}{\sqrt2 \cdot \sqrt2} \\=\dfrac{6\sqrt2}{2}$ Simplify by canceling common factors: $\require{cancel} \\=\dfrac{\cancel{6}3\sqrt2}{\cancel{2}} \\=3\sqrt2$