Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter 5 Test - Page 337: 13



Work Step by Step

RECALL: For non-negative numbers a and b, $\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$ Use the rule above to obtain: $=\sqrt{10(5)} \\=\sqrt{50}$ Factor the radicand so that one of the factors is a perfect square. $=\sqrt{25(2)} \\=\sqrt{5^2(2)}$ Simplify to obtain: $=5\sqrt{2}$
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