Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - Chapter 5 Test - Page 337: 11

Answer

\[-\frac{19}{2}\]

Work Step by Step

As grouping symbol is there, perform the operation inside the parenthesis and then subtract as follows: \[\begin{align} & \left( \frac{1}{2} \right)-8\left( \frac{1}{4}+1 \right)=\left( \frac{1}{2} \right)-8\left( \frac{5}{4} \right) \\ & =\left( \frac{1}{2} \right)-\left( \frac{40}{4} \right) \\ & =\frac{2-40}{4} \\ & =-\frac{38}{4} \end{align}\] Evaluate further as: \[\begin{align} & \left( \frac{1}{2} \right)-8\left( \frac{1}{4}+1 \right)=-\frac{38}{4} \\ & =-\frac{19}{2} \end{align}\] Hence, the value of the provided expression is\[-\frac{19}{2}\].
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