Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.2 Permutations - Exercise Set 11.2 - Page 701: 7



Work Step by Step

The number of possible permutations if r objects are taken from n itself is nPr = $\frac{n!}{(n-r)!}$ The number of different ways you can arrange the books, assuming that the order of the books makes a difference to you, is: 9P9 = $\frac{9!}{(9-9)!}$ = 362880 ways
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.