#### Answer

210

#### Work Step by Step

The number of possible permutations if r items are taken from n items is
nPr = $\frac{n!}{(n-r)!}$
7P3 = $\frac{7!}{(7-3)!}$ = $\frac{7*6*5*4!}{4!}$
Since 4! is in both the numerator and the denominator, cancel 4! in the numerator and the denominator.
7*6*5 = 210