Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.2 Permutations - Exercise Set 11.2: 40

Answer

1

Work Step by Step

The number of possible permutations if r items are taken from n items is nPr = $\frac{n!}{(n-r)!}$ 6P0= $\frac{6!}{(6-0)!}$ = $\frac{6!}{6!}$ =1
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