#### Answer

362880

#### Work Step by Step

The number of possible permutations if r items are taken from n items is
nPr = $\frac{n!}{(n-r)!}$
9P9= $\frac{9!}{(9-9)!}$ = $\frac{9!}{0!}$ = $\frac{362880}{1}$ = 362880
We put 1 on the bottom since 0!=1.

Published by
Pearson

ISBN 10:
0321867327

ISBN 13:
978-0-32186-732-2

362880

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