Chapter 11 - Counting Methods and Probability Theory - 11.2 Permutations - Exercise Set 11.2: 26

6

Work Step by Step

See Factorial Notation, page 696: $n!=n(n-1)(n-2)\cdots(3)(2)(1)$ and, by definition, $0!=1$ ------------ $(6-3)!=3!=3\times 2\times 1=6$

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