#### Answer

6

#### Work Step by Step

See Factorial Notation, page 696:
$n!=n(n-1)(n-2)\cdots(3)(2)(1)$
and, by definition, $0!=1$
------------
$(6-3)!=3!=3\times 2\times 1=6$

Published by
Pearson

ISBN 10:
0321867327

ISBN 13:
978-0-32186-732-2

6

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