Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - 10.5 Volume and Surface Area - Exercise Set 10.5 - Page 658: 47

Answer

The cost of filling the pool is\[\$27\].

Work Step by Step

First of all, compute the radius of the pool using the equation as shown below: \[\begin{align} & \text{Radius}=\frac{1}{2}\times \text{Diameter} \\ & =\frac{1}{2}\times 24\text{ feet} \\ & =12\text{ feet} \end{align}\] In this way, \[r=12\text{ feet}\], and \[h=4\text{ feet}\] In order to determine the cost of filling the pool, one is required to compute the volume of the circular shaped pool with dimensions as\[r=12\text{ feet}\], and\[h=4\text{ feet}\]. Compute the volume of the right circular cylinder using the equation as shown below: \[\begin{align} & \text{Volume of the right circular cylinder}=\pi {{r}^{2}}h \\ & \text{=}\left( \pi {{\left( 12\text{ ft} \right)}^{2}}4\text{ ft} \right) \\ & =\text{576}\pi \text{ f}{{\text{t}}^{\text{3}}} \\ & =1,810.28\text{ f}{{\text{t}}^{\text{3}}} \end{align}\] Thus, the quantity of water for filling the pool is\[1,810.28\text{ f}{{\text{t}}^{\text{3}}}\]. Now, compute the number of gallons of water required to fill the pool as follows: \[\begin{align} & \text{Number of gallons required to fill pool}=\text{Volume of the tank}\times \\ & \text{Capacity of one cubic feet} \\ & =1,810.28\text{ f}{{\text{t}}^{\text{3}}}\times 7.48 \\ & =13,541\text{ f}{{\text{t}}^{\text{3}}} \end{align}\] Now, compute the cost of filling the pool using the equation as shown below: \[\begin{align} & \text{Cost to fill the pool}=\text{Number of gallons required to fill the pool}\times \\ & \text{Cost of water per thousand gallons} \\ & =13,541\times \frac{\$2}{1000}\\&=\$27\end{align}\]
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