Answer
The volume of the Eiffel tower in cubic yards is\[\text{174,240 y}{{\text{d}}^{\text{3}}}\].
Work Step by Step
First of all, convert all the dimensions that are the side of the square base and height into yards as follows:
One can convert the side of the square base as follows:
\[\begin{align}
& 120\text{ feet}=\frac{120\text{ ft}}{1}\times \frac{1\text{ yd}}{3\text{ ft}} \\
& =40\text{ yd}
\end{align}\]
One can covert the height as follows:
\[\begin{align}
& 980\text{ feet}=\frac{980\text{ ft}}{1}\times \frac{1\text{ yd}}{3\text{ ft}} \\
& =\frac{980}{3}\text{ yd} \\
& \approx \text{326}\text{.7 yd}
\end{align}\]
Now, In order to compute the volume of the Eiffel tower, compute the area of the square base using the equation as shown below:
\[\begin{align}
& \text{Area of square base}\left( \text{B} \right)={{a}^{2}} \\
& =\left( 40 \right)\text{ y}{{\text{d}}^{2}} \\
& =1,600\text{ y}{{\text{d}}^{\text{2}}}
\end{align}\]
Thus, the area of the square base is \[1,600\text{ y}{{\text{d}}^{\text{2}}}\]
Now, compute the volume of the Eiffel tower using the equation as shown below:
\[\begin{align}
& \text{Volume of the pyramid}=\frac{1}{3}Bh \\
& =\left( \frac{1}{3}\times 1600\text{ y}{{\text{d}}^{2}}\times \text{326}\text{.7 yd} \right) \\
& =174,240\text{ y}{{\text{d}}^{\text{3}}}
\end{align}\]
