Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 5 - Sequences, Mathematical Induction, and Recursion - Exercise Set 5.6 - Page 302: 11

Answer

See explanation

Work Step by Step

**Solution Explanation** We have a sequence defined by the formula \[ c_n = 2^n \;-\; 1, \quad \text{for all integers } n \ge 0. \] We want to show that it satisfies the recurrence \[ c_k = 2\,c_{k-1} \;+\; 1, \quad \text{for all integers } k \ge 1. \] --- ### Step 1. Express \(c_k\) and \(c_{k-1}\) From the Given Formula \(c_k = 2^k - 1.\) \(c_{k-1} = 2^{k-1} - 1.\) --- ### Step 2. Verify the Recurrence Compute the right-hand side of the recurrence: \[ 2 \, c_{k-1} \;+\; 1 \;=\; 2 \bigl(2^{k-1} - 1\bigr) \;+\; 1 \;=\; 2^k - 2 + 1 \;=\; 2^k - 1 \;=\; c_k. \] Hence, \[ c_k = 2 \, c_{k-1} + 1 \quad \text{for all } k \ge 1, \] as required.
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