Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - Review Exercises - Page 698: 98



Work Step by Step

We are given the equation $b+6=3b-8$. We can solve by first adding 8 to both sides. $b+6+8=3b-8+8$ $b+14=3b$ Subtract b from both sides. $b-b+14=3b-b$ $2b=14$ Divide both sides by 2. $b=7$
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