## Basic College Mathematics (10th Edition)

$b=7$
We are given the equation $b+6=3b-8$. We can solve by first adding 8 to both sides. $b+6+8=3b-8+8$ $b+14=3b$ Subtract b from both sides. $b-b+14=3b-b$ $2b=14$ Divide both sides by 2. $b=7$