Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - Review Exercises - Page 698: 99



Work Step by Step

We are given the equation $-14=2(a-3)$. We can solve the equation by first using the distributive property to simplify the right side. $-14=2(a-3)=2(a)+2(-3)=2a-6$ Add 6 to both sides. $-14+6=2a-6+6$ $2a=-8$ Divide both sides by 2. $a=-4$
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