## Basic College Mathematics (10th Edition)

$y=-5$
We are given the equation $4y-3=7y+12$. We can solve by first adding 3 to both sides. $4y-3+3=7y+12+3$ $4y=7y+15$ Subtract 7y from both sides. $4y-7y=7y-7y+15$ $-3y=15$ Divide both sides by -3. $y=-5$