Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - Review Exercises - Page 698: 85



Work Step by Step

We are given the equation $20=3y-7$. We can solve for y by first adding 7 to both sides. $20+7=3y-7+7$ $3y=27$ Divide both sides by 3. $\frac{3y}{3}=\frac{27}{3}$ Therefore, $y=9$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.