Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - Review Exercises - Page 698: 86



Work Step by Step

We are given the equation $-5=2b+3$. We can solve for b by first subtracting 3 from both sides. $-5-3=2b+3-3$ $2b=-8$ Divide both sides by 2. $\frac{2b}{2}=\frac{-8}{2}$ Therefore, $b=-4$.
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